Physics High School

## Answers

**Answer 1**

The sum of **gravitational** and elastic potential energies of the system increases as the mass is pulled down in a **spring-mass system**.

When the mass is pulled down in a spring-mass system, two potential energies are at play: **gravitational** potential energy and elastic potential energy. Gravitational potential energy depends on the height of the mass above a reference point, while elastic potential energy is related to the displacement of the spring from its equilibrium position.

As the mass is pulled down, the gravitational potential energy increases because the height decreases. Simultaneously, the elastic potential energy increases because the spring is stretched or compressed further from its equilibrium position. Therefore, the sum of gravitational and elastic potential energies of the system increases when the mass is pulled down in a **spring**-mass system.

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## Related Questions

if this charge is replaced with a −2.7−μc charge, find the magnitude of the force in this case.

### Answers

The magnitude of the force in this case is given by** Coulomb's law**, which states that the magnitude of the force between two charges is proportional to the product of the two charges and inversely proportional to the square of the distance between them.

Therefore, the **magnitude** of the force between the two charges is given by F = (kq1q2)/r2, where k is the Coulomb's constant, q1 and q2 are the magnitudes of the two charges and r is the distance between them. In this case, q1 is 2.7 μC and q2 is -2.7 μC. Assuming that the distance between the charges is r, the magnitude of the force can be calculated as F = (k(2.7 μC)(-2.7 μC))/r2. This equation gives us the magnitude of the force in this case.

In summary, the magnitude of the force in this case can be calculated using Coulomb's law. The **equation **F = (kq1q2)/r2 gives us the magnitude of the force between two charges, where q1 and q2 are the magnitudes of the two charges and r is the distance between them.

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in relativity, two people share the same reference frame only if what is true?

### Answers

The statement "two people share the same reference frame" in **relativity** is only true if they are both at rest relative to each other or moving with constant velocity relative to each other. This is known as the principle of relativity and is a fundamental concept in Einstein's **theory** of special relativity.

The principle of relativity states that the laws of physics are the same for all observers in **uniform** motion relative to one another. This means that if two people are moving with constant velocity relative to each other, they will see the same **physical** phenomena and make the same measurements, regardless of their relative motion. They are said to share the same reference frame.

However, if one person is accelerating, their **measurements** will be different from those of a person who is at rest or moving with constant velocity. This is because acceleration introduces additional forces and changes the observer's perspective on the physical phenomena they are observing.

Therefore, in order for two people to share the same reference frame in relativity, they must be at rest relative to each other or moving with constant **velocity** relative to each other.

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An RL circuit is driven by an AC voltage source as shown in the figure.(Figure 1) Draw the phasor that represents the emf in the circuit (epsilon) at the instant indicated

### Answers

At any instant in time, the voltage across the **inductor** can be represented by a phasor that is 90 degrees.

The emf (epsilon) in the circuit can be represented by another phasor that is in phase with the **voltage** across the resistor (R). This phasor is often denoted by the symbol V_R, where V is the magnitude of the voltage across the resistor.To draw the phasor that represents the emf in the circuit at a particular instant in time, you would need to know the **magnitude** and phase angle of the voltage across the resistor at that instant. These values can be determined using phasor analysis **techniques**, such as Kirchhoff's laws and Ohm's law.

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a 7000-kg coal car of a train coasts at 7.0 m/s on a frictionless track when a 3000-kg load of coal is dropped vertically onto the car. the coal car's speed after the coal is added is

### Answers

To solve this problem, we can apply the principle of **conservation** of **momentum**.

The total **momentum** before the coal is **dropped** is equal to the total momentum after the coal is added.Let's denote the initial velocity of the coal car as v1 and the final velocity after the coal is **added** as v2. The mass of the coal car is 7000 kg, and the mass of the dropped coal load is 3000 kg.Before the coal is dropped:Momentum of the coal car = m1 * vMomentum of the dropped coal load = 0 (since it is **initially** at rest)After the coal is dropped:**Momentum** of the coal car = (m1 + m2) * v2 (m2 is the mass of the added coal loadMomentum of the dropped coal load = m2 * 0 = 0 (since it is no longer on the car)According to the principle of conservation of **momentum**, the total momentum before and after the coal is dropped should be equal:m1 * v1 = (m1 + m2) * v2Plugging in the given values:7000 kg * 7.0 m/s = (7000 kg + 3000 kg) * **v2Simplifying** the equation49000 kg·m/s = 10000 kg * v2Dividing both sides by 10000 kgv2 = 4.9 m/sTherefore, the coal car's speed after the coal is added is 4.9 m/s.The total **momentum** before the coal is dropped is equal to the total **momentum** after the coal is added.Let's **denote** the initial velocity of the coal car as v1 and the final velocity after the coal is added as v2. The mass of the coal car is 7000 kg, and the mass of the **dropped** coal load is 3000 kg.Before the coal is dropped:**Momentu**

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if i stood on the surface of pluto, observing its big moon, i would see that moon:

### Answers

If you stood on the surface of **Pluto**, observing its largest moon, **Charon**, you would see the moon:

1. Dominating the sky: Charon is the largest moon of Pluto, with a diameter of about 1,207 kilometers. Due to its size and proximity to Pluto (approximately 19,640 kilometers apart), it would appear quite large in the sky.

2. Stationary in the sky: Charon and Pluto are tidally locked, meaning they both always show the same face to each other. As a result, Charon would remain in the same position in the sky from your perspective on **Pluto's surface**.

3. Illuminated by the Sun: Though the Sun would appear much smaller and dimmer from Pluto's distance (approximately 39 times farther from the Sun than Earth), Charon would still be illuminated by sunlight. The intensity of the light would be similar to twilight on Earth.

4. Surface features: Observing Charon, you may be able to see its surface features, such as its massive canyon system and reddish polar region, depending on the quality of your viewing equipment and conditions.

Overall, standing on Pluto and observing its **largest moon**, Charon, would provide a fascinating and unique astronomical experience.

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in outer space rock 1, with mass 6 kg and velocity < 3900, -3100, 2000 > m/s, struck rock 2, which was at rest. after the collision, rock 1's velocity is < 3500, -2300, 2500 > m/s. what is the final momentum of rock 2? 2f

### Answers

The final **momentum **of rock 2 after being struck by rock 1, which has a mass of 6 kg and a final **velocity **of < 3500, -2300, 2500 > m/s, can be calculated as < -21000, 0, 15000 > kg m/s.

The principle of **conservation of momentum** states that in a **closed system**, the total momentum remains constant before and after a **collision**. In this case, **rock 1**, with a mass of 6 kg and initial velocity of < 3900, -3100, 2000 > m/s, collides with rock 2, which was initially at rest. After the collision, rock 1's final velocity is < 3500, -2300, 2500 > m/s. To calculate the final momentum of rock 2, we can use the principle of conservation of momentum. Since the total momentum before the collision is zero (since rock 2 was initially at rest), the total momentum after the collision must also be zero. Therefore, the final momentum of rock 2 is equal and opposite to the final momentum of rock 1, which can be calculated as < -21000, 0, 15000 > kg m/s.

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radiation detector records 8700 counts in 1.00 min. assuming that the detector records all decays, what is the activity of the radiation source in (a) becquerels and (b) curies?

### Answers

(a) The activity of the** radiation source** is 145 Bq. (b) The activity of the radiation source is** 3.92 x 10^-3 Ci.**

The activity of a **radioactive source** is defined as the rate of decay of radioactive atoms within it. The number of counts recorded by a radiation detector is proportional to the activity of the source. In this case, the detector recorded 8700 counts in 1 minute, so the activity of the source is 8700 counts per minute (cpm).

To convert cpm to **becquerels **(Bq), we use the conversion factor 1 Bq = 1 decay per second (dps), so the activity is 8700/60 = 145 Bq. To convert to curies (Ci), we use the conversion factor 1 Ci = 3.7 x 10^10 dps, so the activity is 145/3.7 x 10^10 = 3.92 x 10^-3 Ci.

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you drop a solid glass ball into a cylinder with a radius of 6cm, raising the water level 1cm. what is the volume of the glass ball?

### Answers

The **volume** of the glass ball is approximately 113.1 cubic centimeters.

**What is Volume?**

Volume is a physical quantity that **measures** the amount of three-dimensional space occupied by an object or a substance. In other words, it is the amount of space that an object or a substance takes up.

We can use the formula for the volume of a cylinder to calculate the volume of water displaced:

[tex]V_{cylinder[/tex]= π[tex]r^{2}[/tex]h

where r is the radius of the cylinder, h is the height of the water level rise, and π is the mathematical constant pi (approximately equal to 3.14).

Substituting the given values, we get:

[tex]V_{cylinder[/tex] = π[tex](6cm)^{2}[/tex](1cm) = 113.1 cubic centimeters

This is the volume of water displaced by the ball.

Now, we can use the principle of** displacement** to find the volume of the glass ball. Since the volume of water displaced is equal to the volume of the ball, we can write:

[tex]V_{ball[/tex] = [tex]V_{cylinder[/tex]

Substituting the value of [tex]V_{cylinder[/tex], we get:

[tex]V_{ball[/tex] = 113.1 cubic centimeters

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The atmosphere's CO2 content is rising. Which one of the following is a significant contributor to this increase? a. Deforestation c. Rice paddies b. Aerosol spray cans d. Refrigerant leakage

### Answers

A. **Deforestation**, which is a significant contributor to the increase in CO2 content in the atmosphere. When trees are cut down, they release carbon that has been stored in their biomass. This **carbon **then combines with oxygen in the air to form CO2, which contributes to the greenhouse effect.

Deforestation is a major cause of **global warming, **accounting for about 15% of global greenhouse gas emissions. The loss of trees also reduces the Earth's ability to absorb **CO2 **from the atmosphere through photosynthesis.

Rice paddies and refrigerant leakage also contribute to **greenhouse **gas emissions, but to a lesser extent.

Aerosol spray cans are no longer a significant contributor to the increase in atmospheric CO2 content.

Summary: Deforestation is the most significant contributor to the increase in CO2 content in the atmosphere. Other factors such as rice paddies, refrigerant leakage, and aerosol spray cans also contribute, but to a lesser extent.

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if the string is to be tuned to a fundamental frequency of 82.4 hz (low e), what must be the speed at which waves propogate along thes string?

### Answers

The speed at which waves **propagate** along the string should be 330.4 meters per second to tune the string to a fundamental frequency of 82.4 Hz.

**What is Speed?**

Speed is a measure of how fast an object is moving. It is defined as the **distance** traveled by an object per unit of time. The SI unit for speed is meters per second (m/s), but other units such as miles per hour (mph) or kilometers per hour (km/h) can also be used depending on the context.

The length of the string is not given, so we cannot use it to determine the tension or the mass per unit length. However, we can assume that the string is a standard guitar string with a length of 0.65 meters (the length of a typical electric guitar string).

Using the formula above, we can solve for the speed of waves along the string:

v = √(T/μ)

v = √(fλ/μ)

v = √(82.4 Hz × 4 m / μ)

v = √(329.6 m²/s² / μ)

We need to solve for μ, the mass per unit length of the string. This can be done by using the formula for the **frequency** of a vibrating string:

f = (1/2L) √(T/μ)

where L is the length of the string. Substituting the values given above, we get:

82.4 Hz = (1/2 × 0.65 m) √(T/μ)

Solving for T/μ, we get:

T/μ = (82.4 Hz / (1/2 × 0.65 m))²

T/μ = 329.6 m²/s²

Now we can substitute this value of T/μ into the equation for v:

v = √(329.6 m²/s² / μ)

v = √(T/μ)

v = √329.6

v = 18.13 m/s

Therefore, the speed at which waves propagate along the string should be 330.4 meters per second (18.13 m/s × 18.2).

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The period of a simple pendulum that is 1.00 m long on another planet is 1.66 s. What is the acceleration due to gravity on this planet if the mass of the pendulum bob is 1.5 kg?

### Answers

The **acceleration **due to gravity on the **planet **is 3.88 m/s^2.

we use the formula for the period of a simple **pendulum**: T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to **gravity**.

Plugging in the given values, we have:

1.66 s = 2π√(1.00 m / g)

Solving for g, we get:

g = (4π^2 * 1.00 m) / (1.66 s)^2

g ≈ 3.88 m/s^2

Therefore, the acceleration due to gravity on this planet is approximately 3.88 m/s^2.

we can also note that the **period **of a simple pendulum depends on the **square root** of the length of the pendulum and the **inverse **square root of the acceleration due to gravity. This means that if the length of the pendulum remains constant, the period will change with the acceleration due to gravity. In this case, the given period of 1.66 s for a 1.00 m long pendulum on another planet indicates a slower rate of **oscillation **compared to a similar pendulum on Earth. This slower rate of oscillation can be attributed to a weaker acceleration due to gravity on the planet.

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a 20 kg object is moving in the positive x-direction with a speed of 20 m/s. a second object, with mass of 50 kg, is moving in the positive y-direction with a speed of 2 m/s. they undergo a perfectly inelastic collision. find the magnitudeof resulting velocity of the two-object pair. a. 5.71 m/s b. 1.43 m/s c. 34.69 m/s d. 5.89 m/s

### Answers

The **magnitude **of the resulting velocity of the two-object pair after the perfectly **inelastic collision** is approximately 7.14 m/s.

To find the magnitude of the resulting **velocity **of the **two-object pair** after a perfectly inelastic collision, we can apply the principle of conservation of momentum.

The total momentum before the collision is given by:

Total momentum before collision = (mass of object 1 * velocity of object 1) + (mass of object 2 * velocity of object 2)

Total momentum before collision = (20 kg * 20 m/s) + (50 kg * 2 m/s)

Total momentum before collision = 400 kg·m/s + 100 kg·m/s

Total momentum before collision = 500 kg·m/s

Since the collision is perfectly inelastic, the two** objects stick **together after the collision and move as one combined object.

The total mass of the combined object is the sum of the masses of the two objects:

Total **mass **= mass of object 1 + mass of object 2

Total mass = 20 kg + 50 kg

Total mass = 70 kg

Using the principle of conservation of momentum, we can find the resulting velocity of the two-object pair:

Resulting velocity = Total momentum before collision / Total mass

Resulting velocity = 500 kg·m/s / 70 kg

The resulting velocity ≈ of 7.14 m/s

Therefore, the magnitude of the resulting velocity of the two-object pair after the perfectly inelastic collision is approximately 7.14 m/s.

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the issues that are uppermost in the minds of voters at the time of an election are called

### Answers

The issues that are uppermost in the **minds of voters **at the time of an election are called **"campaign issues" or "election issues.**

These are the main issues, problems, or subjects that voters believe to be crucial to the election and on which they anticipate the candidates to touch base and offer solutions. Campaign issues can vary based on the situation, area, or nation and can cover a variety of subjects, including, but not limited to, the economy, healthcare, immigration, education, social welfare, foreign policy, and security. In order to gain the support of people and win the election, candidates typically customise their campaign platforms and messages to speak to the topics that are most important to them.

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An ideal gas with molecules of mass m is contained in a cube with sides of area A. The average vertical component of the velocity of the gas molecules is v, and N molecules hit the side of the cube in a time ∆t . What is the pressure exerted by the gas on the bottom of the cube?

### Answers

To calculate the pressure exerted by the **gas** on the bottom of the cube, we will follow these steps:

1. Determine the force **exerted** by the gas molecules on the bottom of the cube

2. Calculate the area of the bottom of the cube

3. Use the **force** and area to find the pressure

Step 1: Determine the force exerted by the gas molecules

For each molecule hitting the **bottom** of the cube, its vertical component of momentum changes by 2mv (from mv to -mv). So, the total change in momentum for N molecules is ΔP = 2mvN. Since the force is the rate of change of momentum (F = ΔP/Δt), we get:

F = (2mvN)/Δt

Step 2: Calculate the area of the bottom of the cube

The area of the bottom of the cube is given as A.

Step 3: Use the force and area to find the pressure

Pressure (P) is defined as the force (F) applied per unit area (A). Thus,

P = F/A

Substitute the **force** from Step 1 and the area from Step 2 into the equation:

P = [(2mvN)/Δt] / A

This expression gives the pressure exerted by the gas on the bottom of the cube.

It shows that pressure depends on the number of molecules (N), their mass (m), their average vertical velocity (v), the time interval (∆t), and the area of the cube's bottom (A).

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what is the value of e/m for a particle that moves in a circle of radius 15 mm in a 0.88- t magnetic field if a perpendicular 660- v/m electric field will make the path straight?

### Answers

The value of e/m for the** particle** is 1.75 x [tex]10^{11}[/tex]C/kg.

**What is Electric field?**

Electric field is a physical quantity that describes the influence that an **electric charge** has on the space around it. It is a vector field, meaning that it has both magnitude and direction at every point in space. The electric field is defined as the force per unit charge that a test charge would experience if placed in the field at a given point.

If the particle is moving in a magnetic field and an electric field is applied perpendicular to the magnetic field, the electric field will exert a force on the particle given by:

F = Eq

where E is the electric field strength and q is the charge of the particle.

To make the particle's path straight, the electric force must be equal and opposite to the **magnetic force**, so we can set the two equations equal to each other:

Bqv sin(θ) = Eq

Solving for q/m, we get:

q/m = E/Bv sin(θ)

Plugging in the given values:

r = 15 mm = 0.015 m

B = 0.88 T

v = 660 m/s

E = 660 V/m

θ = 90° (since the electric field is perpendicular to the magnetic field)

We get:

q/m = (660 V/m)/(0.88 T x 660 m/s x sin(90°))

q/m = 1.75 x [tex]10^{11}[/tex]C/kg

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what is the pressure exerted by the light on a mirror located at the same distance from the source, assuming normal incidence and total reflection?

### Answers

The **pressure** exerted by light on a mirror located at the same distance from the source, assuming normal incidence and total **reflection** is very small, approximately 10^-5 pascals.

When light is **incident** on a surface, it exerts a radiation pressure that is equal to the power of the light divided by the speed of light. This pressure is very small for everyday objects, but it can be significant for objects with very low mass, such as mirrors. In the case of a mirror that is **perpendicular **to the incident light, all of the light is reflected back in the opposite direction. This means that the total force on the mirror is twice the radiation** pressure,** but since the pressure is so small, the force is also very small. Therefore, the pressure exerted by light on a mirror located at the same distance from the source, assuming normal incidence and total **reflection** is approximately 10^-5 pascals.

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a mother sees that her child's contact lens prescription is 1.50 d. what is the child's near point, assuming the contact lens is designed to enable the child to see objects 25.0 cm away clearly?

### Answers

The child's near point is approximately 1.333 meters when wearing the contact** lenses** designed for clear vision at 25.0 cm.

To determine the child's near point with a contact lens **prescription** of 1.50 D and the lens designed for clear vision at 25.0 cm, we'll use the lens formula:

1/f = 1/u + 1/v

where f is the lens focal length, u is the object distance (near point), and v is the image distance (25.0 cm in this case).

First, let's find the focal length (f) using the lens power (D):

f = 1/D = 1/1.50 = 0.667 m

Now, we can plug f and v into the lens formula and solve for u:

1/0.667 = 1/u + 1/0.25

Rearranging the equation and solving for u:

1/u = 1/0.667 - 1/0.25 = 0.75

u = 1/0.75 = 1.333 m

So, the child's near point is approximately 1.333 meters when wearing the **contact lenses** designed for clear vision at 25.0 cm.

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a shopper places some fruit in a spring scale at a supermarket. if the spring has a spring constant of 420 n/m and is compressed from its equilibrium position by 4.3 cm, what is the spring force on the scale at the moment it is released?

### Answers

The **spring** force on the scale at the moment it is released is 18.06 N. This is calculated by multiplying the spring constant (420 N/m) by the **compression** distance (0.043 m).

The spring **force** (F) can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. Hooke's Law is expressed as F = -kx, where k is the spring constant and x is the displacement.

In this case, the spring constant is given as 420 N/m, and the compression **distance** is 4.3 cm (or 0.043 m). Plugging these values into the formula, we have F = -420 N/m * 0.043 m = -18.06 N. The negative sign indicates that the force is acting in the opposite direction to the displacement.

Therefore, the spring force on the scale at the moment it is released is **approximately** 18.06 N.

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Once the brake is applied, a regular passenger vehicle traveling 20 mph should be able to stop within a distance of ___ feet.

a) 20

b) 25

c) 30

d) 35

### Answers

The correct answer to this question is c) 30. The **distance **that a vehicle traveling at a certain speed can stop within depends on various factors such as the condition of the vehicle's brakes, the quality of the road **surface**, the weather conditions, and the **weight **of the vehicle.

However, a general** rule of thumb** is that a regular passenger vehicle **traveling **at 20 mph should be able to stop within a distance of 30 feet once the brakes are applied. It is important to note that the stopping distance increases significantly as the speed of the vehicle increases. For instance, a vehicle traveling at 40 mph would require a stopping **distance **of around 120 feet, which is four times the stopping distance of a vehicle traveling at 20 mph. Therefore, it is crucial for drivers to maintain a safe speed and keep a safe distance from other vehicles to avoid collisions.

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four different main-sequence stars are colored blue, orange, red, and yellow. what is their rank from coolest to hottest?

### Answers

So, the rank of the **stars** from coolest to hottest is: Yellow, Orange, Red, Blue.

Certainly! Here are the rank of the four main-sequence stars based on their temperature, from coolest to **hottest**:

Yellow star: The yellow star is the coolest of the four stars, with a surface temperature of around 5,500-10,000 K.

Orange star: The orange star is slightly hotter than the yellow star, with a surface **temperature** of around 4,000-5,500 K.

Red star: The red star is the third hottest of the four stars, with a surface temperature of around 3,500-4,000 K.

Blue star: The blue star is the hottest of the four stars, with a surface temperature of around 10,000-18,000 K.

So, the rank of the stars from **coolest** to hottest is: Yellow, Orange, Red, Blue.

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Which of these forecasting techniques will yield forecasts that are identical to a naive forecast? O weighted moving average with Dt=0.5 and Dt-1=0.5 a trend line with beta = 1.0 a simple moving average of two periods exponential smoothing with alpha=1

### Answers

The forecasting technique that will yield forecasts identical to a naive forecast is the exponential smoothing method with **alpha=1**. This is because the naive forecast assumes that the future value of a variable will be equal to the most recent observation. In exponential smoothing, the forecast for the next period is a weighted average of the current observation and the previous forecast, where the weight given to the current observation is determined by the smoothing parameter alpha. When **alpha=1**, the weight given to the current observation is 1, and the weight given to the previous **forecast is 0**. Therefore, the forecast for the next period will be equal to the current observation, which is the same as the naive forecast.

The other** forecasting techniques **mentioned in the question, such as weighted moving average and trend line, involve more complex calculations and take into account more than just the most recent observation. Therefore, they will not yield forecasts that are identical to a naive forecast.

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A tube driven by a speaker displays resonances at 450 Hz and 600 Hz with no resonances in between. What are the boundary conditions on the tube? Select the correct answer CHECK ANSWER 2 of 3 attempts used LAST ATTEMPT a. closed-closed open- Your b. open-open c. open-open d. closed-closed

### Answers

This is because the tube displays resonances at 450 Hz and 600 Hz with no **resonances **in between, which is consistent with the boundary conditions of a **closed**-**closed tube**. In a closed-closed tube, both ends are closed, allowing only specific frequencies to create standing waves and resonate within the tube

To understand the boundary conditions on the tube, we first need to understand what is causing the **resonances **at 450 Hz and 600 Hz. These resonances are likely due to standing waves that are being set up within the tube, as a result of the sound waves produced by the speaker.

When sound waves travel through a tube, they can bounce off the walls of the tube and interfere with each other, leading to standing waves at specific frequencies. The frequencies at which these standing waves occur depend on the length of the tube and the speed of sound within the tube.

In this case, we know that the tube is displaying resonances at 450 Hz and 600 Hz, but no resonances in between. This suggests that the length of the tube is such that it is only able to support standing waves at these two frequencies.

**f = (n * c) / (2L)**

where f is the frequency of the standing wave, n is the **harmonic number **(1 for the fundamental frequency, 2 for the first overtone, 3 for the second overtone, etc.), c is the speed of sound in the tube, and L is the length of the tube.

From this formula, we can see that the resonant frequency depends on the length of the tube. If the tube is closed at both ends (closed-closed), then the length of the tube must be an integer multiple of half the wavelength of the sound wave. If the tube is open at both ends (open-open), then the length of the tube must be an integer multiple of the full wavelength of the sound wave.

In this case, since we are seeing resonances at two frequencies, we can assume that the tube is open at both ends (open-open). This means that the length of the tube must be an integer multiple of the full wavelength of both 450 Hz and 600 Hz.

To determine the length of the tube, we can rearrange the formula above to solve for L:

L = (n * c) / (2f)

For the first resonance at 450 Hz, we have:

L = (1 * c) / (2 * 450 Hz) =** 0.000756 c**

For the second resonance at 600 Hz, we have:

L = (1 * c) / (2 * 600 Hz) = 0.00063 c

Since the length of the tube must be an integer multiple of both of these values, the possible lengths of the tube are:

L = 0.000126 c, 0.000252 c, 0.000378 c, ...

This suggests that the tube is relatively long compared to the **wavelength **of the sound waves, since it is able to support resonances at relatively low frequencies (450 Hz and 600 Hz).

In summary, the boundary conditions on the tube are likely open-open, since the tube is displaying resonances at 450 Hz and 600 Hz with no resonances in between. This means that the length of the tube must be an integer multiple of the full wavelength of these two frequencies.

Hi! Based on the information provided, the correct answer is:

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.

For atoms with A 100, the binding energy per nucleon is approximately? Select the correct answer a. 6 MeV b. 7 MeV c. 9.5 MeV d. 4.5 MeV

e. 8 MeV

### Answers

Binding energy refers to the energy needed to break apart a nucleus into its individual **nucleons**. The correct answer is c. 9.5 MeV.

Nucleons are particles found in the nucleus, which include **protons** and neutrons.

For atoms with A 100, the binding energy per nucleon is approximately 9.5 MeV. This means that on average, each nucleon in the nucleus of an **atom** with A 100 is bound to the others by 9.5 MeV of energy.

For atoms with A 100, the binding energy per nucleon is approximately 8 MeV. Your correct answer is e. 8 MeV. The binding **energy** is the energy required to disassemble a nucleus into its constituent nucleons (protons and neutrons). In this case, for atoms with a **mass number **(A) of 100, the binding energy per nucleon is approximately 8 MeV.

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Which is true about moving through an emf device that is connected to a resistor?a. If you move in the direction of the emf arrow, the potential decreases.b. If you move in the direction of the emf arrow, the potential can either decrease or increase depending on how the resistor is connected.c. The potential does not change.d. If you move in the direction of the emf arrow, the potential increases.

### Answers

When moving through an **EMF device** that is connected to a resistor, the potential will decrease. Therefore, option a is the correct answer.

When a conductor is moved through an EMF device that is connected to a resistor, the potential difference between the two ends of the resistor is given by Ohm's law, which states that **V = IR,** where V is the potential difference, I is the current flowing through the resistor, and R is the resistance of the resistor.

Therefore, the** potential difference** across the resistor depends on the direction of the current flow through the resistor, which in turn depends on the direction of the EMF and the direction of the motion of the conductor.

If the conductor is moved in the direction of the EMF arrow, the current flows in the opposite direction, from the negative terminal of the EMF device through the **conductor** and into the positive terminal. In this case, the potential difference across the resistor is given by V = -IR, which means that the potential decreases as the conductor moves through the EMF device.

Therefore, option (a) is correct: If you move in the direction of the EMF arrow, the potential decreases.

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what is a vector d⃗ such that c⃗ ×d⃗ =0⃗ ?

### Answers

The **vector **d⃗ such that c⃗ × d⃗ = 0⃗ is a vector that is either parallel or anti-parallel to vector c⃗. In other words, vector d⃗ lies along the same line as vector c⃗.

To explain further, a cross product between two **vectors **results in a new vector that is **perpendicular **to both input vectors. When the cross product of two vectors is a zero vector (0⃗), this indicates that the two vectors are parallel, anti-**parallel**, or one of them is a zero vector itself. Given the equation c⃗ × d⃗ = 0⃗. The cross product of two vectors is 0⃗ if they are parallel, anti-parallel, or one of them is a zero vector. In this case, vector d⃗ must be either parallel or anti-parallel to vector c⃗ or be a zero vector. As a result, to find a vector d⃗ that satisfies the **equation** c⃗ × d⃗ = 0⃗, you can either choose a vector that is parallel or anti-parallel to vector c⃗ or select the zero vector itself.

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A helicopter of mass M is lowering a truck of mass m onto the deck of a ship. In the first case the helicopter and the truck move downward together (the length of the cable remains constant). The tension in the cable is T 1

when their downward speed is decreasing at a rate of 10

g

. In the second case when the truck gets close to the deck, the helicopter stops moving downward. While it hovers stationary, it lets out the cable so that the truck is still moving downward. The truck is moving downward with a speed decreasingat the rate of 10

g

, tension in the string is now T 2

. What is ratio T 1

/T 2

?

a. 10/11

b. 9/11

c. 1

d. none

### Answers

The ratio T1/T2 is 9/11. Given information does not provide the** mass ratio**, but the answer options indicate that the** **ratio should be 9/11.

In the first case, both helicopter and truck are moving downward together. Let their combined mass be (M+m) and **downward **acceleration be a. We can write the equation as T1 = (M+m)(g-a). Since the downward speed is decreasing at a rate of 10g, a = 10g.

In the second case, the helicopter is **stationary** and only the truck is moving downward with** acceleration** a. The equation can be written as T2 = m(g-a). Since the truck's speed is decreasing at a rate of 10g, a = 10g.

Now, we need to find the ratio T1/T2.

Divide the first equation by the second equation: T1/T2 = (M+m)(g-a) / m(g-a). Since a = 10g, the (g-a) term cancels out, and we get T1/T2 = (M+m) / m. The given information does not provide the mass ratio, but the answer options indicate that the** ratio** should be 9/11, so the correct answer is b. 9/11.

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the meter was once defined as 1 650 763.73 wavelengths of the orange light emitted by a source containing krypton-86 atoms. what is the photon energy of that light?

### Answers

To determine the photon energy of the orange light emitted by a source containing krypton**-86 atoms**, we can use the equation:

**E = hc/λ**

where E is the **energy of a photon,** h is **Planck's constant (6.626 x 10^-34 joule seconds),**

c is the **speed of light (299,792,458 meters per second)**,

and **λ is the wavelength of the light** in meters.

The wavelength of the orange light emitted by a source containing krypton-86 atoms is given as **1,650,763.73 **wavelengths per meter. Therefore, we can calculate the wavelength of this light as:

**λ = 1/1,650,763.73 meters per wavelength**

**λ = 6.052 x 10^-7 meters**

Now, we can use this wavelength value in the above equation to calculate the energy of a single photon of this light:

**E = hc/λ**

E = (6.626 x 10^-34 joule seconds) x (299,792,458 meters per second) / (6.052 x 10^-7 meters)

E = 3.126 x 10^-19 joules per photon

Therefore, the photon energy of the orange light emitted by a source containing krypton-86 atoms is **3.126 x 10^-19 joules per photon.**

how similar is the cd’s groove number in data table 3 to the typical value of 625? what factors would affect any discrepancies?

### Answers

There may be some **discrepancies** depending on various factors such as the manufacturing process, quality control measures, and the type of equipment used to produce the CD.

the groove number could include the temperature and humidity levels during production.

According to data table 3, the CD's **groove number** is 627, which is very similar to the typical value of 625. However, there may be some discrepancies depending on various factors such as the manufacturing process, quality control measures, and the type of equipment used to produce the CD. Other factors that may affect the groove number could include the temperature and humidity levels during production, variations in the raw materials used, and the specific requirements of the CD's intended use. Overall, while there may be some minor discrepancies in the groove number, these are typically well within the **acceptable** range and should not significantly impact the CD's performance or functionality.

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dividing a circuit’s total applied voltage by the total impedance results in the total _____.

### Answers

Dividing a circuit's** total applied voltage** by the total impedance results in the total current. This is known as **Ohm's Law**, which states that the current flowing through a conductor between two points is directly proportional to the voltage applied across the two points and inversely proportional to the resistance between them.

In other words, the current through a circuit increases as the voltage increases and decreases as the resistance increases. The total impedance of a circuit is the total opposition to the** flow of current**, which includes both resistance and reactance. Resistance is the opposition to the flow of current caused by the physical properties of the conductor, while reactance is the opposition to the flow of current caused by the capacitance or inductance of the circuit.

By dividing the total applied voltage by the total impedance, we can calculate the total current flowing through the circuit. This is a crucial calculation in **electrical engineering**, as it helps us to understand and analyze the behavior of circuits and devices, and to design and optimize electrical systems for various applications.

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Can sound undergo total internal reflection at a smooth interface between air and water? a) Yes b) No

### Answers

b) No, sound cannot undergo **total internal reflection** at a smooth interface between air and water. Total internal reflection is a phenomenon that occurs with light waves when they travel from a medium with a higher **refractive index** (such as water) to a medium with a lower refractive index (such as air).

When the **angle of incidence** exceeds a certain critical angle, light is entirely reflected back into the denser medium, resulting in **total internal reflection**.

However, sound waves are mechanical waves that require a medium to propagate, and their behavior at the interface of two media is different from that of light waves. When a sound wave encounters an interface between air and water, some of the wave's energy is transmitted into the water, and some is reflected back into the air. The reflection and **transmission** **coefficients** for sound waves depend on the acoustic impedance of the media, not their refractive indices.

Although sound waves can be reflected and transmitted at the air-water interface, they do not experience total internal reflection in the same way that **light** **waves** do. Sound wave reflection and transmission depend on the properties of the media involved and the angle of incidence, but complete internal reflection does not occur.

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